How do you add two 16 bit numbers in assembly language?
Algorithm –
- Load both the lower and the higher bits of first number at once.
- Copy the first number to another register pair.
- Load both the lower and the higher bits of second number at once.
- Add both the register pairs and store the result in a memory location.
How can I get 16 bit number in 8086?
8086 program to Print a 16 bit Decimal number
- load the value stored into register.
- divide the value by 10.
- push the remainder into the stack.
- increase the count.
- repeat the steps until the value of the register is greater than 0.
- until the count is greater than zero.
- pop the stack.
How can I add two numbers in 8086?
8086 program to add two 8 bit BCD numbers
- Load data from offset 500 to register AL (first number)
- Load data from offset 501 to register BL (second number)
- Add these two numbers (contents of register AL and register BL)
- Apply DAA instruction (decimal adjust)
- Store the result (content of register AL) to offset 600.
How do you add two numbers in assembly language?
Algorithm –
- Load the first number from memory location 2050 to accumualtor.
- Move the content of accumulator to register H.
- Load the second number from memory location 2051 to accumaltor.
- Then add the content of register H and accumulator using “ADD” instruction and storing result at 3050.
How do I put two 64-bit numbers on a 32 bit machine?
Adding two 64-bit numbers cannot be done with a single instruction like addition for 32-bit numbers. The addition must be done in two stages – first the lower 32 bits and then the upper 32 bits. The result of the two lower 32 bits is stored in the lower 32 bits of the result.
How can I add two 32 bit numbers in 8085?
- Start the program by loading the first data into Accumulator.
- Move the data to a register (B register).
- Get the second data and load into Accumulator.
- Add the two register contents.
- Check for carry.
- Store the value of sum and carry in memory location.
- Terminate the program.
What is the 64 bit limit?
Limits of processors In principle, a 64-bit microprocessor can address 16 EBs (16 × 10246 = 264 = 18,446,744,073,709,551,616 bytes, or about 18.4 exabytes) of memory. However, not all instruction sets, and not all processors implementing those instruction sets, support a full 64-bit virtual or physical address space.