How many different ways can a 9 player baseball team be selected for an informal game if there are 25 available players which counting method do you use?
225 ways, using Combinations of 25 taken by 9. 2,045,975 ways, using Combinations of 25 taken by 9.
How many ways can you pick 10 players to take the field?
858 ways
How many ways can a baseball team manager arrange nine players in a lineup?
A baseball team has 9 starting players. How many ways can the coach make out the batting order? 9! = 9 · 8 · 7 · 6 · 5 ·4 · 3 · 2 · 1 = 362,880 .
How many ways can they choose a president vice president secretary and treasurer?
5040 different ways
How many ways can a 30 member group elect a president and vice president?
There are 30 ways to fill the president slot. Leaving 29 people to fill the V.P. slot and 28 people to fill the Sec/ Treas slot since you wouldn’t want one person to have two of those jobs. Therefore, the solution is or 24,360 ways.
How many ways can a president and vice president be selected from 12?
1320 ways
How many ways can a group of 5 be chosen from 25?
So there are 53,130 different ways to form a group of 5 people.
How many ways can a president vice president and secretary be chosen from a club with 7 members?
210 WAYS
How many ways can a committee of 5 be selected from a club with 10 members?
252 ways
How many ways can a committee of 4 be selected from a club with 10 members?
210
How many ways can a committee of 4 be selected from a club with 12 members?
The options it gives for answers are: 12. 48.
How many ways can 2 students be chosen from 10 students?
90 different ways
How many ways can a committee of 4 be chosen from 7?
35 ways
How many ways can a committee of 3 be selected from a club with 12 members?
455 ways
How many ways can a committee of 3 be selected from a club with 10 members?
720
How many combinations of 3 students can be selected from a group of 9 students?
Therefore, the 3 groups can be chosen 84 x 20 x 1 = 1680 ways. However, since the order of the 3 groups doesn’t matter, we have to divide 1680 by 3!. Hence, the number of ways 9 people can be divided into 3 groups is 1680/3! = 1680/6 = 280.
How many ways can 10 beads be formed in a bracelet?
Answer: This is called a cyclic permutation. The formula for this is simply (n-1)!/2, since all the beads are identical. Hence, the answer is 9!/2 = 362880/2 = 181440.
How many necklaces can you make with 6 beads of 3 colors?
the answer is 60, but how? Question 883539: how many necklaces can be made from 6 beads of different colors? the answer is 60, but how? There are 6 beads in that necklace and each one is a different color.
How many ways can 7 beads can be arranged to form a necklace?
Permutation and Combination #39
| 39. In how many ways can 7 beads can be arranged to form a necklace? | |
|---|---|
| A. 360 | B. 120 |
| C. 720 | D. 60 |
How many different ways can 5 Charms be placed on a bracelet that has a clasp?
120 ways
How many necklaces can you make with 8 beads of colors?
2520 Ways 8 beads of different colours be strung as a necklace if can be wear from both side.
What is the difference between permutation and combination?
A permutation is an act of arranging the objects or numbers in order. Combinations are the way of selecting the objects or numbers from a group of objects or collection, in such a way that the order of the objects does not matter.
How many s’s does Mississippi have?
In the word Mississippi there are 11 letters. 4 s’s 4 i’s 2 p’s 1 m.
What is the probability that four S COM consecutively in the word Mississippi?
The number of ways in which four S come consecutively in the word MISSISSIPPI, is. together in 4! 4! =1 way.
How many arrangements of the letters in Mississippi have consecutive S’s?
We know from problem #1 there are 34,650 permutations of MISSISSIPPI and we now know that 7,350 arrangements have no adjacent S’s, so to find the permutations with at least 2 adjacent S’s simply take the difference. So there are 27,300 permutations with 2 or more adjacent S’s.
How many ways can banana be arranged?
There are 3×2×1 = 6 ways to rearrange the A’s and 2×1 = 2 ways to rearrange the N’s. So, there are: 720/(6×2) = 720/12 = 60 ways to rearrange all the letters in BANANA.
What is the rank of the word banana?
36
What is the value of 7C3?
Answer. Step-by-step explanation: Now, 7C3 = 7! / (7 – 3)!
How many ways can you permute the letters in banana?
60