Why do two balls one falling vertically and the other horizontally land at the same time?
The horizontal and vertical motions of a projectile are independent of each other. So two objects falling under the influence of gravity from the same height will reach the ground simultaneously, regardless of their horizontal velocities.
What will happen to the range when you double the velocity?
As the vertical component of the velocity has been doubled, it will take gravity twice as long to pull it back to Earth, meaning it stays airborne twice as long. The horizontal component has also been doubled, so it travels horizontally twice as fast for twice as long, meaning the range increases by a factor of four.
What happens to time if initial velocity is doubled?
You should change “Velocity” to “Speed.” If you double the speed, the time of arrival of your plane will be sooner. For example: Instead of 6 hours flight, your plane will arrive in 3 hours, if your plane doubled the speed to fly.
What will be the effect on maximum height?
Answer. Maximum height will increase to 3 times that of initial.
What does not affect the maximum height of projectile?
Magnitude of initial velocity.
For what angle of projection height is maximum?
Complete step by step answer: If the angle of projection is 75.96∘, the maximum height is equal to the horizontal range.
What will be the effect on horizontal range of a projectile?
Answer. Thanks for asking the question. According to this formula the range of projectile is directly propotional to the square of the initial velocity. So when the initial velocity is doubled the range of projectile becomes four times as per the formula where as the angle of projectile remains un changed.
What is the effect of increasing the angle of projection on the range of a projectile?
Range of projectile, R For θ = 45°, sin 2θ = sin 90° = 1 (maximum). In the nutshell, the range,R, increases with increasing angle of projection for 0° ≤ θ < 45°; the range,R, is maximum when θ = 45°; the range,R, decreases with increasing angle of projection for 45° < θ ≤ 90°.
What is the angle of projection for a projectile motion whose range R is N times the maximum height?
Find the angle of projection for a projectile motion whose rang R is (n) time the maximum height H. or tanθ=4norθ=tan-1(4/n). Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.
At which point of the trajectory is the speed of motion minimum?
A projectile have a minimum speed at the highest point of its trajectory. This is because horizontal speed of the projectile remains constant. Since the only force exerted on the projectile is gravity, which is 9.8 ms2 acting downwards and has no effects on the horizontal velocity.