When two resistors have resistance R1 and R2 are connected in parallel?

When two resistors have resistance R1 and R2 are connected in parallel?

When two resistors, having resistance R1 and R2, are connected in parallel, the equivalent resistance of the combination is 5 Ω. When two resistors, having resistance R1 and R2, are connected in parallel, the equivalent resistance of the combination is 5 Ω.

When two resistances R1 and R2 are connected in parallel what is the equivalent resistance?

The equivalent resistance value for 2 resistors in parallel is calculated with these steps: The above equation shows that if R1 is equal to R2 Req is half of the value of one of the two resistors. For a Req of 9 ohms, R1 and R2 should therefore have a value of 2×9=18 ohms.

What is the equivalent of two resistors joined in series?

When two resistors are joined in series the equivalent resistance is 90 ohms. When the same resistors are joined in parallel, the equivalent resistance is 20 ohms.

How do you calculate percent error in parallel resistance?

Let Rp denote parallel combination. So, error in Rp will be 223% of 2003, which is approximately 4.89. Hence, I got Rp=66.67±4.89 ohm. However, the book used the formula described and proved here and arrived at the answer Rp=66.67±1.8 ohm.

What is total resistance in parallel with possible percentage error?

What is the total resistance in parallel with possible % error? Text Solution. Solution : In parallel , RP=R1R2R1+R2=5.0×10.05.0+10.0=5015=3.3Ω Also ΔRPRP×100=ΔR1R1×100+ΔR2R2×100+Δ(R1+R2)R1+R2×100.

When two resistors of resistances R1 and R2 are connected in parallel the net resistance is 3?

When two resistors of resistance R1 and R2 are connected in parallel , the net resistance is 3 ohms . When connected in series its value is 10 ohms .

How do you calculate percent error of resistance?

Calculate the percentage error in the specific resistance, ρ=πr2R/l, where r=radius of the wire =0.26±0.02cm, l=length of wire =156.0±0.1cm, and R=Resistance of the wire=64±2Ω.

When two resistors R1 and R2 are connected in parallel then their parallel combination is given by RP R1R2 R1 R2?

Answer: However if you have only two resistors in parallel, then the calculation is much straight forward. R = R1R2 / R1 + R2 where R is the total resistance and R1, R2 are two individual resistors connected.