Are irrational numbers computable?
In fact, since only countably many irrational numbers can be computed, “most” irrational numbers are not computable! This fact comes as a shock to students and gives a great demonstration of the importance of understanding the difference between countable and uncountable sets.
Are computable numbers countable?
In the usual set theoretic tradition computable real numbers are countable since there are only a countable quantity of Turing Machines. Thus real computable number are countable, but not effectively countable, i.e. you cannot give a computable bijection from the natural numbers onto the real computable numbers.
What is a non computable function?
Yet there are also problems and functions that that are non-computable (or undecidable or uncomputable), meaning that there exists no algorithm that can compute an answer or output for all inputs in a finite number of simple steps.
Which of the following set of computable functions are Decidable?
Explanation: According to rice theorem, it is undecidable to determine whether the language recognized by an arbitrary turing machine lies in S. 4. Which of the following set of computable functions are decidable? Explanation: All of the following mentioned are immediate results of Rice’s theorem and thus, undecidable.
Which among the following are incorrect regular identities?
Which among the following are incorrect regular identities? Explanation: The given statement is the Arden’s Theorem and it tends to have a unique solution as QP*. Explanation: The regular expression is fragmented and the set of the strings eligible is formed. ‘+’ represents union while ‘.
Which of the following problems are decidable?
1) This is a variation of Turing Machine Halting problem and it is undecidable. 2)CFL are not closed under complement so it is undecidable. 3) Complement of Regular languages is also regular. 4) Recursvie language are closed under complement,so it is decidable.
Which of the following belongs to the epsilon closure set of A?
Discussion Forum
| Que. | Which of the following belongs to the epsilon closure set of a? |
|---|---|
| b. | {a, f1, f2, f3} |
| c. | {f1, f2} |
| d. | none of the mentioned |
| Answer:{a, f1, f2, f3} |
Is the language preserved in all the steps while eliminating Epsilon transitions from a NFA?
Is the language preserved in all the steps while eliminating epsilon transitions from a NFA? Explanation: Yes, the language is preserved during the dteps of construction: L(N)=L(N1)=L(N2)=L(3).
What is epsilon closure of a state?
Epsilon (∈) – closure : Epsilon closure for a given state X is a set of states which can be reached from the states X with only (null) or ε moves including the state X itself.
Which one is true according to Epsilon NFA?
2. State true or false? Statement: An NFA can be modified to allow transition without input alphabets, along with one or more transitions on input symbols. Explanation: It is possible to construct an NFA with ε-transitions, presence of no input symbols, and that is called NFA with ε-moves.
What is ε NFA *?
Nondeterministic finite automaton with ε-moves (NFA-ε) is a further generalization to NFA. This automaton replaces the transition function with the one that allows the empty string ε as a possible input. The transitions without consuming an input symbol are called ε-transitions.
How do I remove Epsilon from NFA?
Eliminating ε Transitions
- Find out all the ε transitions from each state from Q.
- Then δ’ transitions can be obtained.
- Repeat Step-2 for each input symbol and each state of given NFA.
- Using the resultant states, the transition table for equivalent NFA without ε can be built.
What is NFA null?
An NFA with null transition is allowed to make transition not only on input from the alphabet but also with null input, i.e. without any input symbol. This transition without input is called null transition.
How do you find the null closure?
Step 1: We will take the ε-closure for the starting state of NFA as a starting state of DFA. Step 2: Find the states for each input symbol that can be traversed from the present….For state C:
- δ'(C, 0) = ε-closure {δ(q4, 0) }
- = ϕ
- δ'(C, 1) = ε-closure {δ(q4, 1) }
- = ϕ
What is the difference between e NFA and NFA?
Non-deterministic Finite Automata (NFA) is a finite automata having zero, one or more than one moves from a given state on a given input symbol. Epsilon NFA is the NFA which contains epsilon move(s)/Null move(s).
Why is NFA slow?
NFA is slower to process and its representation uses more memory than DFA. DFA is faster to process and its representation uses less memory than NFA. NFA is slower to process and its representation uses less memory than DFA.
Which is more powerful DFA or NFA?
A DFA is just a special case of an NFA that happens not to have any null transitions or multiple transitions on the same symbol. So DFAs are not more powerful than NFAs. For any NFA, we can construct an equivalent DFA (see below). So NFAs are not more powerful than DFAs.
What is mealy FSM?
In the theory of computation, a Mealy machine is a finite-state machine whose output values are determined both by its current state and the current inputs. This is in contrast to a Moore machine, whose (Moore) output values are determined solely by its current state.
Is Moore or Mealy machine better?
-Mealy machines (generally) have less states. -Moore machines may be safer to use, because they change states on the clock edge (if you are using DFF logic for present and next state), whereas Mealy machines are faster, because the state is dependent on the input. Thus, the state can change asynchronously.