How can 2 ohm 3 ohm and 6 ohm be connected to give an effective resistance of 4 ohm?
Answer. Answer: Put 3 ohms in parallel with 6 ohms to produce an equivalent of 2 ohms by the parallel equivalent resistance rule [1/(1/3 + 1/6) = 2] Place that parallel combination in series with the other 2 ohms to get 4 ohms, since series resistances simply add [2+2=4].
How can three resistors of Resistance 2 ohm 3 ohm and 6 ohm?
The arrangement of three resistors of 2,3Ω and 6Ω which gives a total resistance of 4Ω can now be represented as follows: Thus, we can obtain a total resistance of 4Ω by connecting parallel combination of 3Ω and 6Ω resistors in series with 2Ω resistor.
How would you connect 3 resistors each of Resistance 6 Ohm?
Answer. To obtain a combined resistance of 9 ohms, three resistors each of resistance 6 ohm should be connected in a parallel circuit and one in series. In a parallel circuit, the equivalent resistance of all the resistors connected is equal to the reciprocal value of the sum of the individual resistances.
What is highest and lowest resistance which can be obtained by combining?
1 Answer. (a) For obtaining the highest resistance by combining the given resistances, we must connect them in series. (b) For obtaining the lowest resistance by combining the given resistances, we must connect them in parallel.
What is the lowest resistance that?
Ans: Given resistances R1 =4 Ω, R2=8 Ω, R3=12Ω, and R4=24Ω. ∴ 2 Ω is the lowest total resistance.
What is the highest resistance that you can get using all of them?
Answer. Answer: The least resistance that one can have from six resistors of each 0.1 ohm resistance is: A . 0.167 Ω.
What is the lowest resistance that can be obtained by resistors?
When the resistors are connected in parallel, the result we get is the lowest resistance. In parallel combination, Hence, the lowest resistance is 2 ohms.
What is ratio of highest and lowest resistance which can be obtained by combining four resistors having the 4 ohm resistance?
What is (a) the highest, (b) the lowest total resistance that can be secured by combinations of four coils of resistance 4 Ω, 8 Ω, 12 Ω, 24 Ω? R = 4 + 8 + 12 + 24 = 48 Ω. (b) Lowest resistance can be obtained by connecting the four coils in parallel.
What is the effective resistance between A and B in the given network?
R = 25/10.