How many ways can 8 horses lineup for a race?
For example, if all horses finish in a different place, then the number of ways the horses can finish is simply 8! = 40320.
How many ways can horses finish in 1st 2nd & 3rd place of 18 horses started the race?
Given the identity of the horse that comes second, the horse that comes third can be any of the remaining 10 horses. So the number of different ways in which 1st, 2nd and 3rd can occur is 12 x 11 x 10 = 1,320.
How many ways can the horses finish first second and third in a 6 horse race?
Any one of the 3 horses could finish first and then the other two are tied. Similarily there are 3 outcomes with exactly 2 horses tied for first. All that remains is the 1 situation where all three horses tie for first. Thus, in total there are 6 + 3 + 3 + 1 = 13 different outcomes.
How many ways can 10 horses come in first second and third?
There are 720 different outcomes possible in the race.
How many ways can first second and third place be awarded to 7 contestants?
The first prize can be won by any of the 7 racers. The second prize can be won by one of the remaining 6 racers. And the third prize can be one by one of the remaining 5 racers. 7 x 6 x 5 = 210 ways the prizes can be awarded.
How many different ways can you have a 1st 2nd 3rd and 4th place finisher with 15 runners?
And for 4th place, you can have any one of the 12 runners who haven’t finished finish there. So, you take all of the possibilities, and times them together, 15*14*13*12 = 37,260 different possibilities.
How many ways can 5 runners come in 1st 2nd 3rd place?
60 different possible ways
How many ways can 6 runners finish in 1st 2nd and 3rd place?
Now, there is a 6th runner added to the race. He can occupy either 1st or 2nd or 3rd or 4th or 5th or 6th place. So, there can be 1*2*3*4*5*6 = 720 ways to finish the race.
How many different ways can you pick 1st 2nd and 3rd place winners from a group of 8 individuals?
There are 8 choices for awarding first prize. Then there are 7 choices for awarding second prize. And there are 6 choices for awarding third prize. Therefore, there are: 8 *7 *6 =336 ways.
How many ways can the top 3 winners be selected?
Problem Answer: There are 455 ways the three winners are to be chosen.
How many different ways can the first second and third place prizes be awarded?
= 720 different possible ways the 3 prizes are awarded. P.S. Do you have a text book or something that talks about counting the number of ‘outcomes’ ?
How many ways can three people be selected from a group of seven people if order does matter?
How many ways can three people be selected from a group of seven people if order DOES matter? If order does matter, then there are seven ways to select Person #1, six ways to select Person #2, and five ways to select Person #3: 7 x 6 x 5 = 210. Welcome! How can I help with your math homework question?
How many ways can three people be selected from a group of 12?
220 possible combinations
How many ways can a committee of 3 Be Chosen 10?
3! (10−3)! = 120.
How many ways can a group of 5 be chosen from 25?
Expand 25! Expand 20! Expand 5! So there are 53,130 different ways to form a group of 5 people.
How many ways can a group of 5 be chosen from 30?
Therefore: You can arrange 30 students into 6 groups if 5 in 30! ÷(5!+
How many 4 committees can you make from a group of 25?
so there are such people committees, form that can be formed in total from people (including all male and all female committees), that’s roughly . Number of distinct 4 person committees that can be selected from among 25 people = 25!/(21!)( 4!) = 12,650.
How many ways can 5 students be selected from a group of 8?
So, number of possible seating arrangements = 0. Therefore, the answer will be: (36 + 24 + 12 + 12 + 6 + 0) = 90. So, there are 90 possible seating arrangements.
What does the N and R mean in permutations?
n = total items in the set; r = items taken for the permutation; “!” denotes factorial.