Under what condition can the electric flux linked with a surface be positive?

Under what condition can the electric flux linked with a surface be positive?

If a net charge is contained inside a closed surface, the total flux through the surface is proportional to the enclosed charge, positive if it is positive, negative if it is negative.

How do you increase flux?

There is another way of increasing the flux in the circuit: make the field stronger. This is like bringing a magnet closer to the circuit. So the flux in the circuit changes whether we: move the wire in a steady field or.

Is the incoming flux equal to the outgoing flux?

The value of the incoming flux is approximately equal to the value of the outgoing flux, but opposite in sign.

What condition would allow us to have the incoming flux be equal to the outgoing flux?

The incoming flux is almost equal to the outgoing flux (it may not have been equal due to lack of accurate technology or human error). They are equal because according to Faraday’s law of induction, any change in the magnetic environment of a coil of wire will cause a voltage (emf) to be induced in the coil.

What causes the outgoing peak to be higher than the incoming peak?

Why is the outgoing peak higher than the incoming peak? The second peak (outgoing peak) is higher than the incoming peak because the magnet is moving faster during the second ‘half’ of the fall, and induces a smaller voltage.

What is outgoing flux?

We know that. Flux, Where q=Total charge enclosed by the surface. Substitute the values. Hence, the outgoing flux through the surface will be zero.

What accounts for the different directions for the outgoing and incoming peaks?

The peaks are opposite in direction because the change in magnetic field at one end of the coil isopposite to the change in magnetic field at the other end. Faraday’s law predicts that the direction of theinduced voltage is dependent on the nature of the change in magnetic field.

Why is the induced emf zero when the coil is passing directly through the center of the magnet?

At some point, the bar reaches the middle of the coil. At this point, the amount of flux added to the top half of the coil by a small motion of the magnet is equal to the amount of flux removed from the bottom half. Therefore, at this point the EMF is zero.

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