What is SI unit of merit?
Figure of merit is the amount of current been passed in the unit of deflection in a galvanometer. Its SI unit is Ampere per division.
What’s the difference between a galvanometer and a multimeter?
The galvanometer is converted into the ammeter by connecting the resistance in parallel with the circuit. And if the resistance is connected in series with a galvanometer, then it is used as a voltmeter….Comparison Chart.
| Basis for Comparison | Galvanometer | Ammeter |
|---|---|---|
| Type of Device | Mechanical | Mechanical or Electronic. |
Does galvanometer have resistance?
Galvanometer has small resistance. The construction of the galvanometer is same as that of the ammeter but the only difference between an ammeter and a galvanometer is that the ammeter has additional resistance connected in parallel with the circuit.
Can a galvanometer measure voltage?
A galvanometer can be made into a voltmeter to measure voltage by connecting a high resistance in series. Once the galvanometer is converted into a voltmeter it should be connected parallel to the circuit just like a voltmeter.
Why does the galvanometer deflect?
When the magnet is moved away from the coil, the galvanometer shows deflection in the opposite direction indicating that the direction of the induced current is reversed.
What happens to the deflection of the galvanometer pointer as?
The direction of deflection in a galvanometer is reversed if the direction of motion (or polarity of the magnet) is reversed. This indicates that whenever there is a change in the magnetic flux linked with a coil, an emf is induced.
What does it mean when a galvanometer reads zero?
With the unknown resistance Rx in the circuit, R3 is adjusted until the galvanometer reads zero. The potential difference between points b and d is then zero, meaning that b and d are at the same potential. With no current running through the galvanometer, it has no effect on the rest of the circuit.
How do you calculate the current galvanometer?
1 Answer
- Let current I = 1A split as shown in the figure.
- Current through AB = I1
- Current through BC = I1 – x.
- Cureent through AD = I2
- Current through DC = I2 + x.
- Current through G = x.
- ∴ At junction C,
- I1 – x + I2 + x = I1 + I2 = I = 1 A.