What is the maximum and minimum resistance which can be made?
While equivalent resistance increases when resistors are joined in series e.g., Req = R₁ + R₂ + R₃ + …. + Rn. it Means, we can get minimum resistance when all the given resistors will join in parallel. And we can get maximum resistance when all the resistors will join in series .
What is the maximum and minimum resistance which can be made by using five Resistorseach of 1/5 Ω?
What is the minimum resistance which can be made using five resistors each of (1/5)Ω ? Minimum resistance is obtained in parallel combination. Thus, Rp=(1/5Ω)5=(1/25)Ω.
What is the maximum resistance which can be made using 5?
Answer. the maximum resistance which can be made using 5 resistors each of 1/5 ohms is 1 ohm.
What is the maximum resistance which can be made using 5 resistors each of 15 ohm?
The answer is (d) 1 Ω Maximum resistance is obtained when resistors are connected in series.
What is the effective resistance between A and B?
therefore the effective resistance between A and B is 10Ω
What is the minimum resistance which can be made using 5 resistors of 20 ohm?
So, the minimum resistance which can be made using five resistors is 0.04 ohms.
What is the maximum resistance which can be made using 5 resistors each of 1.5 volt?
Solution : Maximum resistance is obtained in series combination. Thus, Rs=5(15Ω)=1Ω.
What is the ratio of maximum and minimum resistance?
Hence, he ratio of the maximum to minimum resistance that can be obtained by combining them is n2.
How will you connect multiple resistance to get maximum resistance?
i) To get the maximum resistance, the resistors should be in a series combination. ii) To get the minimum resistance, the resistors should have a parallel combination. where, n is the number of resistors. Two wires of equal length, one of aluminium and the other of copper have the same resistance.
What is the resistance from A to B in the network shown in the figure?
The answer is (R/3).
What is the resistance between A and B?
The three resistance of 20 ohm, 10 ohm and 20 ohm on the extreme right side are in series. So, the resultant of these three resistances = 20 + 20 + 10 = 50 ohms. Now, the resistances 10 ohms, 18.75 ohms and 10 ohms are in series. Therefore, resultant resistance = 18.75 + 10 + 10 = 38.75 ohms.
What is the resistance between A and B in the network given below?
Therefore, the equivalent resistance of the given network of resistors between point A and point B is equal to 2Ω. Hence, the correct answer is option D.