What is the probability of getting at least one red marble?
(The chance of getting at least one red marble, on the other hand, is 3/12 + 3/12 – (3/12 × 2/11), or only 10/22.)
What is the probability of selecting a blue marble?
1/5
What is the probability of selecting a green marble?
1/4
What is the probability of drawing 2 red marbles?
Note that there are 16 total marbles. A is simply a set of sequential events. On the first, you have 10/16 chances to draw a red. Supposing this red is not replaced, the chance of drawing a second red will be 9/15; therefore, the probability of A is (10/16) * (9/15) = 0.375.
What are the odds of choosing a red marble from a bag that contains two blue marbles one green marble and four red marbles?
Therefore: P (a red marble is selected in the first attempt) = Red Marbles / Total Marbles. P (a red marble is selected in the first attempt) = 4/7. Therefore, the correct answer is 4/7!!!
What is the probability of picking 2 balls of the same color?
0.44
What is the probability that both marbles are the same color?
Thus, calculate the probability that the marbles are the same color, then subtract this probability from 1 to find the probability they are different colors. P(2 of the same) = P(2 green) + P(2 yellow) + P(2 red) = 1/26 + 5/26 + 2/26 = 8/26 = 4/13. P(2 different) = 1 – P(2 of the same) = 1 – 4/13 = 9/13.
What is the probability that Maria will pick two red marbles if she returns the first marble to the bag?
What is the probability that Maria will pick two red marbles if she returns the first marble to the bag? p((red))p((red))=(4/8)(4/8) answer: A. 3/14 B.
What is the probability that all the marbles are red?
0.009569 Correct
How do you do probability without replacement?
For example, a marble may be taken from a bag with 20 marbles and then a second marble is taken without replacing the first marble. The sample space for the second event is then 19 marbles instead of 20 marbles. This is called probability without replacement or dependent probability.
What is without replacement in probability?
Sampling without Replacement is a way to figure out probability without replacement. In other words, you don’t replace the first item you choose before you choose a second. This dramatically changes the odds of choosing sample items.
What does without replacement mean in probability?
Without replacement: When sampling is done without replacement, each member of a population may be chosen only once. In this case, the probabilities for the second pick are affected by the result of the first pick. The events are considered to be dependent or not independent.
How many different outcomes are possible for 6 rolls of a die?
We can view the outcomes as two separate outcomes, that is, the outcome of rolling die number one and the outcome of rolling die number two. For each of 6 outcomes for the first die the second die may have any of 6 outcomes, so the total is 6+6+6+6+6+6=36, or more compactly, 6⋅6=36.
When one die is rolled six outcomes are possible?
| Trial | Outcomes | Examples of Events |
|---|---|---|
| Rolling a die | There are 6 possible outcomes: {1, 2, 3, 4, 5, 6} | Rolling an even number: {2, 4, 6} Rolling a 3: {3} Rolling a 1 or a 3: {1, 3} Rolling a 1 and a 3: { } (Only one number can be rolled, so this outcome is impossible. The event has no outcomes in it.) |
What is the probability of getting 2 or 3 heads?
Probability of Getting 2 Heads in 3 Coin Tosses
| for 2 Heads in 3 Coin Flips | ||
|---|---|---|
| Atleast 2 Heads | Exactly 2 Heads | |
| Total Events n(S) | 8 | 8 |
| Success Events n(A) | 4 | 3 |
| Probability P(A) | 0.5 | 0.38 |
What is the probability of getting 2 heads and 2 tails?
37.5%
What is the probability of getting 3 heads in 3 tosses?
0.13
What is the probability of getting 2 heads in 4 tosses?
So, we divide by another 2! to cancel out double counting of two T’s. Finally, if we divide all 6 different ways of getting exactly 2 heads (and 2 tails) in 4 flips by all possible outcomes 2 * 2 * 2 * 2 = 16 we would get the probability of exactly 2 heads in 4 flips.
What is the probability of getting at least 2 heads?
Hence the probability of getting at least 2 heads is 48=12.
What is the probability of getting either 4 heads or 4 tails?
1 in 16
What is the probability of getting 3 heads in 4 tosses?
0.25
What is the probability of getting 3 heads?
(Whew!) As you can count for yourself, there are 10 possible ways to get 3 heads. Thus, the probability of getting 3 heads from 5 coin flips is: 10/32, or 5/16.
How many different ways are there to get 3 heads in 10 flips of a coin?
1201024
What is the probability of getting 5 heads in 10 tosses?
252/1,024