Why is it a good idea to start with room temperature water in the calorimeter?
It is a good idea to start with room temperature water in the calorimeter because the room temperature water helps to determine the heating up/cooling down because of the environment as the experiment takes place. Because the calorimeter heat is the same as the heat of the water.
What would be the overall outcome of starting the procedures with cold water instead of room temperature water?
Explanation: Cold water is more dense and therefore it can slow down electrolysis process. The efficiency of electrolysis increases with increase in temperature of the water. If cold water is used then the process will be slowed down.
Why did we ignore the calorimeter in our calculation Although it is listed in the original equation?
Why did we ignore the calorimeter in our calculation, although it is listed in the original equation? The calorimeter was ignored because when an object warms, it expands, and it has to push against the atmosphere to do that.
Should the initial temperature of the water in the calorimeter affect the value of the metal’s specific heat?
Lowering the temperature of the metal during the transfer to the calorimeter is not going to change the specific heat capacity of the metal, because you are measuring the CHANGE in the temperature of of the metal as it cools off. The specific heat capacity of the metal will not change.
What is the final temperature of water?
Therefore, your water increases in temperature by 6 degrees Celsius. Add the change in temperature to your substance’s original temperature to find its final heat. For example, if your water was initially at 24 degrees Celsius, its final temperature would be: 24 + 6, or 30 degrees Celsius.
How do you calculate the temperature of water mix?
Calculate the final temperature of the water mixture using the equation T(final) = (m1_T1 + m2_T2) / (m1 + m2), where m1 and m2 are the weights of the water in the first and second containers, T1 is the temperature of the water in the first container and T2 is the temperature of the water in the second container.
What is the final temperature of the water and the aluminum?
You need to look up the specific heat values (c) for aluminum and water. This solution uses 0.901 for aluminum and 4.18 for water: (10)(130 – T)(0.901) = (200.0)(T – 25)(4.18) T = 26.12 °C.
How do you find the temperature change of metal?
Subtract the final and initial temperature to get the change in temperature (ΔT). Multiply the change in temperature with the mass of the sample. Divide the heat supplied/energy with the product. The formula is C = Q / (ΔT ⨉ m) .