What causes an object to weight?
Weight is the result of gravity . The gravitational field strength of Earth is 10 N/kg (ten newtons per kilogram). This means an object with a mass of 1 kg would be attracted towards the centre of Earth by a force of 10 N. We feel forces like this as weight.
How does the weight of body gradually decreases from?
Answer: Weight of a body is the force experienced by the body due to gravity. The weight of a body decreases with increase in distance from the earth ‘s surface because weight is inversely proportional to the distance of body from the surface of earth.
At what height from the earth surface does the acceleration due to gravity decreases by 1%?
It is given that the acceleration due to gravity at the height h reduces by 1%. Thus the new acceleration due to gravity is g′=0⋅99g . where g is the acceleration due to gravity on the surface of the earth and RE is the radius of the earth.
When a body of mass m is taken from the Earth’s surface to a height h the loss in weight is what?
Answer. Formulas used here are considering R >>> h. Therefore, when weight of body decreases by 1 % at height h, it will decease to 1/2 × 1 = 0.5 % at same depth.
When a body of mass is taken from the Earth’s surface to a height the loss in weight is what?
Weight fo a body of a mass m decreases by 1% when it is raised to height h above the earth’s surface. If the body is taken to depth h in a mine, change in its weight is. Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.
Where the weight of the body is maximum?
Now the weight of the body is directly proportional to the acceleration due to the gravity on the surface of the earth. So the weight of the body is maximum at the poles and minimum at the equator on the surface of the earth.
When a body of mass m is taken to the bottom of a mine its weight?
A body of mass mm is taken to the bottom of a deep mine. Then its weight decreases because acceleration due to gravity decreases.
At what depth the weight of a body becomes half the weight on the surface of Earth?
Where, d is the depth at which g’ is measured and R is the radius of Earth. Therefore, at a depth halfway to the centre of the earth, the weight will be W2 if W was the weight of the same body on the earth’s surface.
What will be the weight at Centre of Earth?
At centre of earth, value of g is zero. Hence, weight is zero.
What is the weight of body at Earth surface?
Since g=9.80m/s2 g = 9.80 m/s 2 on Earth, the weight of a 1.00-kg object on Earth is 9.80 N: w=mg=(1.00kg)(9.80m/s2)=9.80N. w = m g = ( 1.00 kg ) ( 9.80 m/s 2 ) = 9.80 N . When the net external force on an object is its weight, we say that it is in free fall, that is, the only force acting on the object is gravity.
At what height above the surface of the earth the value of g is half?
If we use 6,371 km as Earth’s radius, the distance above the surface where gravitational acceleration is halved would be 2,639 km.
At what height above the surface of Earth the value of G becomes 36?
We can write the relation between actual acceleration due to gravity and the apparent acceleration due to gravity. Hence, the height above the surface of the earth where the acceleration due to gravity is reduced by 36% of its value on the surface of the earth is R4 . The correct option is (B).
At what height above the surface of Earth the value of G becomes 25?
Therefore, at height 6400 km, the acceleration due to gravity is 25% of the acceleration due to gravity at the surface of the earth.
At what height above the surface of Earth the value of g is same as in a mine 80 km deep?
Answer Expert Verified. ⇒ h = 40 Km (Ans.)
At what height above the surface of Earth the value of g decreases by 2 %? Radius of the Earth is 6400 km?
Answer (2) Acceleration due to gravity above the surface of earth at a height h is given 2 ‘ 1 ⎛ ⎞ ⎜ ⎟ ⎝ ⎠ e h g g R here, g ‘ = 0.98 g 2 0.98 1 e h R 2 0.02 e h R h = 0.01 R = 0.01 × 6400 km = 64 km 17.
How much is below the surface of the earth?
Therefore, 1920km below the surface of earth does the acceleration due to gravity become 70% of its value at the surface of earth. Was this answer helpful?
What is the acceleration due to the gravity on Earth?
9.8 m/s/s
When a body of mass m is taken from the surface of the earth to a height N times the Earth’s radius the change in its potential energy would be?
A body of mass m taken from the earth’s surface to the height equal to twice the radius (R) of the earth. The change in potential energy of the body will be. mg2R. 2/3 mgR.
At what height from the surface of the Earth is the gravitational potential?
at what height from surface of earth the gravitational potential and value of g are -5.4*10^5 J kg^-1 and 6.0 m s^-1 respectively. take the radius of earth as 6400 km.
What will be the kinetic energy needed to project a body of mass m from the earth surface to infinity?
The kinetic energy needed to project a body of mass m from the earth surface (radius R) to infinity is. (d) mgR/4.
What is the increase in potential energy of the body with mass m if the body is taken at the height h which is equal to the radius of the earth?
If a body of mass m is moved to a height equal to the radius of the earth R (above the surface, then the increase in its potential energy is 12mgR. Hence, (C) is the correct option. Note: There are two crucial points which you should be careful of.
Which of the following proves there is a gravitational force between the earth and the sun?
Answer. The Sun’s gravitational pull keeps our planet orbiting the Sun. The motion of the Moon is affected by the gravity of the Sun AND the Earth. The Moon’s gravity pulls on the Earth and makes the tides rise and fall every day. …