When two tuning forks are sounded simultaneously 4 beats per second are heard?
When two tuning forks (fork 1 and fork 2) are sounded simultaneously, 4 beats per second are heard. Now, some tape is attached on the prong of the fork 2. When the tuning forks are sounded again, 6 beats per second are heard.
When two tuning forks A and B are sounded together 5 beats per second?
Two tuning forks A and B when sounded together, produce 5 beats per second. The frequency of B is 512 Hz. It is observed that if one prong of A is slightly scraped, then the number of beats increases Determine the frequency of A.
Why does adding tape to a tuning fork lower the frequency?
When waxed, we add the mass of wax to the tuning fork, but this was hardly increases the stiffness of the fork. Thus the denominator rises more than numerator and hence results in a lower frequency.
How do you increase the frequency of a tuning fork?
The pitch that a particular tuning fork generates depends on the length of its prongs. Each fork is stamped with the note it produces (e.g. A) and its frequency in Hertz (e.g. 440 Hz). Shorter prongs produce higher pitch (frequency) sounds than longer prongs.
What happens if tuning fork is waxed?
Tuning fork A when sounded with a tuning fork B of frequency 480 Hz gives 5 beats per second. When the prongs of A are loaded with wax, it gives 3 beats per second.
Does wax increase frequency?
(1) Loading or filing of one prong of known or unknown (by wax) tuning fork, so frequency changes (decreases after loading, increases after filing).
What happens to frequency when a tuning fork is filed?
when the prongs are loaded, their inertia increases, resulting in decrease of vibrational frequency. similarly, when the mass is removed by filing the prongs, their inertia decreases resulting in increase of vibrational frequency.
How do you solve tuning fork problems?
- Consider case – 1, before filing the prongs. Frequency of Tuning fork A = nA= 480 Hz. Number of beats heard = 4 per second.
- Frequency of Tuning fork C = nC= 384 Hz. Number of beats heard = 4 per second.
- Number of beats heard = 6 per second. ∴ Frequency of the note = n = (514 ± 6) Hz.